How Is Strain Calculated in a Composite Concrete and Steel Column Under Load?

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SUMMARY

The calculation of strain in a composite concrete and steel column under a load of 9 kN involves understanding the individual contributions of each material to the overall stress and deformation. The modulus of elasticity for concrete is 20 GPa, while for steel it is 200 GPa. To find the individual stress for each material, one must first calculate the load distribution between the concrete and steel, ensuring that the total load equals the sum of the loads carried by both materials. The strains in both materials will be equal, allowing for the application of the stress-deformation relationship.

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  • Understanding of composite material mechanics
  • Knowledge of stress and strain calculations
  • Familiarity with modulus of elasticity concepts
  • Ability to perform area calculations for structural components
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  • Learn how to calculate load distribution in composite columns
  • Study the stress-deformation relationship for materials with different moduli of elasticity
  • Explore the principles of axial loading in structural engineering
  • Investigate the effects of material properties on structural performance
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Civil engineers, structural engineers, and students studying composite materials in structural applications will benefit from this discussion.

Batman1
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Homework Statement


A Concrete column 2M in height 100mm in diameter and containing four steel rods each at 15mm diameter calculate the stress and the amount the column is compressed due to the load of 9Kn. the modulus of elasticity for the concrete (in this case) is 20GPa and for the steel its 200GPa. I have worked out the total area of the steel bars to be 0.706856X10^-3 (meters squared) and the concrete to be 0.00785398 (meters squared).
But I don’t know how to work out the strain value (must be same for both materials) or the amount of force acting on the separate materials.


Homework Equations


Force = force of material 1 + force of material 2 (concrete and steel)
Stress of material A = total force/area of A X force acting on A


3. The Attempt at a Solution
I have tried several but they have all been incorrect because I can not find the individual stress for each material.

4. Thank you in advance for anyone who can help me to solve this problem
(see attachment for the Question.)
 

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Batman1 said:

Homework Statement


A Concrete column 2M in height 100mm in diameter and containing four steel rods each at 15mm diameter calculate the stress and the amount the column is compressed due to the load of 9Kn. the modulus of elasticity for the concrete (in this case) is 20GPa and for the steel its 200GPa. I have worked out the total area of the steel bars to be 0.706856X10^-3 (meters squared) and the concrete to be 0.00785398 (meters squared).
But I don’t know how to work out the strain value (must be same for both materials) or the amount of force acting on the separate materials.


Homework Equations


Force = force of material 1 + force of material 2 (concrete and steel)
Stress of material A = total force/area of A X force acting on A


3. The Attempt at a Solution
I have tried several but they have all been incorrect because I can not find the individual stress for each material.

4. Thank you in advance for anyone who can help me to solve this problem
(see attachment for the Question.)
You must first calculate the load acting on the left column support (you don't specifically say if you have done this, but it is not 9kN). Then, yes, the strains (and deformations) would be equal in both materials, so you may write the stress-deformation equation as a function of E and A for each material, and set the deformations equal. Then you need to take note of the fact that the loads (not the stress) carried by each material must sum to the total column load. Then you can now calculate all the requested values.
 
Last edited:

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