How Is the Average Energy Calculated in Statistical Mechanics?

Click For Summary
The average energy of a system with energy defined as E = α|x| is being questioned, with the assumption that it relates to a distribution function in statistical mechanics. The discussion suggests that the equipartition theorem may not apply due to the nature of the energy expression. Participants are seeking guidance on which statistical distribution to use, given that the answer involves kT, indicating a temperature dependence. The conversation emphasizes the need for clarity on the appropriate statistical mechanics concepts to derive the average energy. Understanding the correct distribution function is crucial for solving the problem.
Kara386
Messages
204
Reaction score
2

Homework Statement


If the energy of a system depends on ##E = \alpha |x|## where ##\alpha## is positive, what is the average energy of the system?

Homework Equations

The Attempt at a Solution


I've been given no information at all about the system beyond the energy. This is within a statistical mechanics course so I assume it involves some sort of distribution function, but as to which one I have no idea. Alternatively it may be related to equipartition theorem because that's what the previous question was about, although that only deals with quadratic contributions to energy I think.

Apparently the answer is ##kT##. I'd really appreciate some pointers on how to get there! :)
 
Physics news on Phys.org
Kara386 said:
This is within a statistical mechanics course so I assume it involves some sort of distribution function, but as to which one I have no idea.
...
Apparently the answer is ##kT##.
Since the answer involves ##T##, which distribution function do you think is most appropriate?
 

Similar threads

Replies
6
Views
2K
Replies
4
Views
579
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K