How Is the Average Force on a Shell Calculated Using the Work Energy Theorem?

[razzmatazz]

Homework Statement

A weapon fired a 25.8-kg shell with a muzzle speed of 880 m/s. What averageforce acted on the shell?

Homework Equations

work energy theorem?

The Attempt at a Solution

Can someone please explain where the 6.00 comes from?

Starting from rest, the shell acquired a kinetic energy of (1/2)mv2

by a force, F,acting through a distance, d.Fd = (1/2)mv2
F(6.00) = (1/2)(25.8)(880)2
F = 1664960 N = 1.66 MN

 

[tiny-tim]

welcome to pf!

hi razzmatazz! welcome to pf!

6 m must be the length of the muzzle (didn't the question say so?)