How Is the Average Force on a Shell Calculated Using the Work Energy Theorem?

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SUMMARY

The average force acting on a 25.8-kg shell fired at a muzzle speed of 880 m/s is calculated using the work-energy theorem. The equation used is Fd = (1/2)mv², where F is the force, d is the distance (6.00 m, the length of the muzzle), m is the mass, and v is the velocity. Substituting the values, the average force is determined to be 1,664,960 N, or 1.66 MN.

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Homework Statement



A weapon fired a 25.8-kg shell with a muzzle speed of 880 m/s. What averageforce acted on the shell?

Homework Equations



work energy theorem?

The Attempt at a Solution



Can someone please explain where the 6.00 comes from?

Starting from rest, the shell acquired a kinetic energy of (1/2)mv2

by a force, F,acting through a distance, d.Fd = (1/2)mv2
F(6.00) = (1/2)(25.8)(880)2
F = 1664960 N = 1.66 MN
 
Last edited:
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welcome to pf!

hi razzmatazz! welcome to pf! :wink:

6 m must be the length of the muzzle (didn't the question say so?) :smile:
 

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