How Is the Distribution of B_s Given B_t Computed in Brownian Motion?

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SUMMARY

The distribution of B_s given B_t in standard Brownian motion, where 0 ≤ s < t, is computed as a normal distribution. The discussion clarifies that the computation involves conditioning on the σ-algebra generated by B_t. The justification for this computation relies on the properties of Wiener processes, specifically the non-overlapping nature of the distributions.

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  • Understanding of Brownian motion and Wiener processes
  • Knowledge of conditional distributions in probability theory
  • Familiarity with σ-algebras and their applications
  • Basic concepts of normal distributions
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Mathematicians, statisticians, and researchers in stochastic processes who are analyzing conditional distributions in Brownian motion.

IniquiTrance
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I computed the distribution of B_s given B_t, where 0\leq s &lt;t and \left\{B_t\right\}_{t\geq 0} is a standard brownian motion. It's normal obviously..

My question is, how do I phrase what I've done exactly? Is it that I computed the distribution of B_s over \sigma(B_t)?
 
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Hey IniquiTrance.

If you partition the distributions so that they don't overlap then you can use the properties of a Wiener (or Brownian motion) process and that should be enough in terms of the justification used.
 

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