How Is the Mass of Block B Calculated in a Friction-Affected Pulley System?

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SUMMARY

The mass of block B in a friction-affected pulley system is calculated using the equation [mA * g * sin(theta) - mA * g * cos(theta) * Uk] / g, where mA represents the mass of block A, g is the acceleration due to gravity, Uk is the coefficient of kinetic friction, and theta is the angle of the incline. The system operates under the condition of constant speed, indicating zero acceleration. The tension in the rope is equal on both sides, leading to the derived formula for block B's mass.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of friction coefficients, specifically kinetic friction (Uk)
  • Familiarity with basic trigonometry, particularly sine and cosine functions
  • Concept of tension in pulley systems
NEXT STEPS
  • Study the effects of varying the coefficient of friction on pulley systems
  • Learn about the dynamics of non-constant speed in pulley systems
  • Explore advanced pulley system configurations and their equations
  • Investigate the role of angles in inclined plane physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators teaching concepts related to forces and motion in pulley systems.

martyk
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Homework Statement



In figure 6-36, two blocks are connected over a pulley. The mass of block A is mA and the coeffcient of kinetic friction between A and the incline is Uk. Angle of the incline is theta. Block A slides down the incline at constant speed. What is the mass of block B? Express your answer in terms of the variables given.

http://img121.imageshack.us/img121/9748/fig636.gif

Homework Equations



F = ma

The Attempt at a Solution



Taking acceleration to be 0, because speed is constant. And that T1 = T2, i came to the answer of

[m1gsin(theta) - m1gcos(theta)Uk] / g = mass of the 2nd block

Can I get a verification
 
Last edited by a moderator:
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Yes, that is correct.
 

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