How Is the Mass of Each Hailstone Calculated?

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Homework Help Overview

The discussion revolves around calculating the mass of hailstones during a thunderstorm, specifically focusing on hailstones with a diameter of 2.2 cm and their estimated density. Participants are examining the relationship between volume, density, and mass in the context of this problem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are discussing the formula for the volume of a sphere and its application to find the mass of each hailstone. There are questions about the calculations and the interpretation of the results, particularly regarding the mass of individual hailstones versus the total mass.

Discussion Status

The discussion is ongoing, with participants attempting to clarify the calculations and identify any misunderstandings. Some guidance has been offered regarding the correct interpretation of the problem, but there is no explicit consensus on the correct mass of each hailstone yet.

Contextual Notes

Participants are working under the assumption that the density of hail is similar to that of ice, and there may be confusion regarding the calculations leading to the total mass versus the mass of a single hailstone.

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Homework Statement

During a violent thunderstorm, hail the size of marbles (diameter = 2.2 cm) falls at a speed of 36 m/s. There are estimated to be 40 hailstones per cubic meter of air. Assume that, as for ice, 1 cm3 of hail has a mass of 0.92 g. What is the mass of each hailstone?

Homework Equations

volume of a sphere


The Attempt at a Solution

(4∏r^3)/3=5.58 x 0.92=5.13g x 40 stones=205.17g its not right for some reason even tho i used this number to solve the next problem and got that one right ...
 
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hi omc1! :smile:
omc1 said:
What is the mass of each hailstone?

(4∏r^3)/3=5.58 x 0.92=5.13g x 40 stones=205.17g

erm :redface:each hailstone! :wink:
 
oh duh!
 
he he :biggrin:
 

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