How Is the Mass of Earth's Atmosphere Calculated?

  • Thread starter Thread starter rlmurra2
  • Start date Start date
  • Tags Tags
    Atmosphere Mass
Click For Summary
The mass of Earth's atmosphere can be calculated using various methods, primarily involving integration of density as a function of altitude. The thin shell method is suggested, where volume is determined by integrating the density over the height of the atmosphere. Approaches vary in complexity, from simple calculations using surface pressure and gravity to more intricate models that account for the Earth's shape and temperature variations. The integration process requires understanding how density decreases with altitude and how this affects the overall mass. Ultimately, the choice of method depends on the desired accuracy and the assumptions made about atmospheric conditions.
rlmurra2
Messages
19
Reaction score
0
What is the mass of the Earth's atmosphere? The radius of the Earth is 6.4E6m.

The only thing I can think of is to subtract something from the mass of the entire Earth or something...
 
Physics news on Phys.org
rlmurra2 said:
What is the mass of the Earth's atmosphere? The radius of the Earth is 6.4E6m.

The atmosphere is a thin band of gas surrounding a solid/liquid earth, but one can use thin shell method of calculating the thickness of that band.

So V = \int_{R_i}^{R_o} 4\pi\,\rho(r)\,r^2\,dr

or V = 4\pi\,R^2\,\int_0^H \rho(z)\,dz, where R would be the mean radius of the atmosphere referenced from the center of the earth.

Then one needs to integrate as a function of altitude, since density decreases with increase in altitude.

Height of Earth's atmosphere - http://www.rcn27.dial.pipex.com/cloudsrus/atmosphere.html

http://en.wikipedia.org/wiki/Earth's_atmosphere

That should give you enough information.
 
Last edited by a moderator:
Given a radius, can you calculate a surface area? Given an area and a "std." atmospheric pressure can you calculate a total force? Given that force and an "average" value for acceleration of gravity at the Earth's surface, can you calculate anything else of interest?
 
Really, how you do this depends on your approach to the problem:

Easy (this is probably what you want to do)- determine the difference in the acceleration due to gravity at the high and low ends of the atmosphere. This will (probably) allow you to make a very nice simplifying assumption so you can get a good approximation quickly and easily using the surface air pressure, the acceleration of gravity, and the surface area of the earth.

Medium - Integrate by shells assuming that the Earth is spherical, and the temperature of the atmosphere is constant. Remember that the density is proportional to the pressure.

Hard - Integrate but account for the fact that the Earth is a spinning elipsoid and for temperature with respect to lattititude and altititude.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
9
Views
2K
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K