How is theta obtained when using torque = F*r*sin(theta)?

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SUMMARY

The discussion clarifies that in the equation torque = F * r * sin(theta), theta is defined as the angle between the force vector (F) and the position vector (r). The torque can be calculated using the cross product, τ = r × F, which emphasizes the importance of measuring the angle between these two vectors. It is essential to consider the direction of the torque, assigning positive or negative values based on whether the torque is clockwise (cw) or counterclockwise (ccw). The discussion concludes that using the included angle between F and r simplifies the calculation of torque.

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Homework Statement


For the equation torque = F*r*sin(theta), is theta obtained from either angle:
F makes with r (or perpendicular component of F makes with r, or the perpendicular component of r makes with F)?


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The Attempt at a Solution

 
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Torque can be written as \tau = \vec{r} \times \vec{F} so one must measure the angle between r and F.

So find r then measure the angle created by F. So basically we're looking at the perpendicular component of F.
It would make no sense if it was the component of the moment arm r.
 
I find it best when using T = Frsin theta to use theta as the included angle between F and r, then assign a positive or negative value to it depending on whether the torque is cw or ccw. It is often easier, however, depending on the problem, to calculate torque as the product of the force times the perpendicular distance from the line of action of the force to the point about which you are calculating the torque, with appropriate plus or minus sign.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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