How is Total Displacement Calculated for a Two-Part Train Journey?

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A train travels 58km at an average velocity of 77km/h[E] waits for 5min, and then runs for half an hour at an average velocity of 64km/h[E]. Find the total displacement.


HOW?!?? I am so confused. I have a test tomorrow and my teacher is useless. Please help me pass this course.
 
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aaquib said:
A train travels 58km at an average velocity of 77km/h[E] waits for 5min, and then runs for half an hour at an average velocity of 64km/h[E]. Find the total displacement.


HOW?!?? I am so confused. I have a test tomorrow and my teacher is useless. Please help me pass this course.

You shoudl know that aevrage velocity is given by

[tex]\overline{v}_x = \frac{\Delta x}{\Delta t}[/tex]

so if you have the time and the average velocity you may find the displacement. Find the displacements for each of the two different intervals and simply add them up. That's really that simple.
 
kdv said:
You shoudl know that aevrage velocity is given by

[tex]\overline{v}_x = \frac{\Delta x}{\Delta t}[/tex]

so if you have the time and the average velocity you may find the displacement. Find the displacements for each of the two different intervals and simply add them up. That's really that simple.

I only have the time for the second part though. It doesn't tell me how long it travels for until after it stops.
 
distance = velocity / time

You know 58km at an average velocity of 77km/h so you only have one variable, time.
 
aaquib said:
I only have the time for the second part though. It doesn't tell me how long it travels for until after it stops.

For the second part it tells you that it last half an hour!
 

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