The discussion revolves around calculating total displacement for a two-part train journey involving different velocities and a waiting period. The subject area pertains to kinematics and average velocity concepts.
The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the formula for average velocity, but there is no explicit consensus on how to proceed with the missing time information for the first part of the journey.
Participants note that the problem does not provide the time for the first part of the journey, which is causing confusion. There is also mention of a waiting period that may affect the overall calculation.
aaquib said:A train travels 58km at an average velocity of 77km/h[E] waits for 5min, and then runs for half an hour at an average velocity of 64km/h[E]. Find the total displacement.
HOW?!?? I am so confused. I have a test tomorrow and my teacher is useless. Please help me pass this course.
kdv said:You shoudl know that aevrage velocity is given by
[tex]\overline{v}_x = \frac{\Delta x}{\Delta t}[/tex]
so if you have the time and the average velocity you may find the displacement. Find the displacements for each of the two different intervals and simply add them up. That's really that simple.
aaquib said:I only have the time for the second part though. It doesn't tell me how long it travels for until after it stops.