How Is Work Calculated Along a Semicircle in Vector Calculus?

[HeisenbergW]

Homework Statement

Find the work done along the semicircle (x-1)²+y²=1 from the point (0,0,0) to (2,0,0)
When F=r³cos²φsinφ\hat{r} + r³*cosφ*cos(2φ) \hat{φ}

Homework Equations

Work
W=∫F*dr
where dr=dr= dr\hat{r} + rsinφdφ\hat{φ}

The Attempt at a Solution

I convert the equation of the line (x-1)²+y²=1 to cylindrical coordinates.
Where x=rsinφ
and y=rcosφ
so (x-1)²+y²=1
eventually becomes r=2cosφ

now i plug in this r value into the force vector given, which gives me F=8cos⁵φsinφ\hat{r} + 8*cos⁴φ*cos(2φ) \hat{φ}

W=∫F*dr

So now i dot product this with the dr, which is now dr= dr\hat{r} + 2cosφ
sinφdφ\hat{φ} due to the r value I found.

The dot product comes out to be

∫8cos⁵φsinφdr + 16*cos⁵φ*cos(2φ)sinφdφ

and because r=2cosφ, dr=-2sinφ dφ

so this is once again plugged into the integral of the dot product, creating

∫-16cos⁵φsin²φdφ + 16*cos⁵φ*cos(2φ)sinφdφ

where I integrate from pi/2 to 0, since it ends at x=2 and y=0, but begins at x=0 and y=0

This gives me -4/35, which does not seem to be a correct answer
Any mistakes?
Any help is appreciated
Thank You in advance

 

[ehild]

where dr=dr= dr\hat{r} + rsinφdφ\hat{φ}

The equation is not correct.The second terms has to be rdφ\hat{φ}.
And make the vector \vec{dr} different from dr, change of the coordinate r.


ehild

 

[HeisenbergW]

For d\vec{r} I actually left out the second term, which is the elevation angle, since it is constant. I guess I should have clarified that I am using this in spherical coordinates, but I did produce a typo It should be
dr\hat{r}+rsinθd\varphi\hat{\varphi}.
Which of course just simplifies to
dr\hat{r}+rd\varphi\hat{\varphi}
because θ constantly equals pi/2
So you can ignore the lone sin at the end of the force vector, since it goes to one. Yet it still goes to a negative value unfortunately.

 

[ehild]

The integration path is not clear: You can reach from (0.0,0) to (2,0,0) along the upper semicircle or the bottom one, yielding integrals of opposite signs.

ehild

 

[HeisenbergW]

My apologies, we must go along the circle where y>0

 

[ehild]

The integral is negative then.

ehild