How Is Work Calculated for a Moving Crate?

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Homework Help Overview

The discussion revolves around calculating the work done on a crate being moved across a factory floor. The original poster presents a scenario involving a drag line and an electric motor, with specific values for force and distance provided.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to verify their calculation of work done using the formula WD=F*S, questioning the relevance of the force value provided in their textbook.

Discussion Status

Participants are engaged in clarifying the problem context and the assumptions regarding the force acting on the crate. Some guidance has been offered regarding the calculations, but there is no explicit consensus on the interpretation of the force involved.

Contextual Notes

The original problem context includes a specific setup involving the movement of crates across rollers, and there is a request for the full problem statement to ensure accurate understanding. The original poster has calculated various parameters related to the crate's movement but seeks confirmation on the work done.

joe465
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Homework Statement



Calculate the work done on the crate during the journey

Homework Equations



WD=F*S

The Attempt at a Solution



I know its simple but I am just double checking more than anything, the force pulling the crate is 482.96N and the distance is 20M.

Now i would presume 482.96*20= 9659.2J

My book however says that the force is the force we are opposing against so what force would this be?

Thanks, Joe
 
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Can you please post the full problem exactly as given.
 
The first of these concerns the transport of crates
across the floor of a factory. This is accomplished by using a drag line connected
to an electric motor. Crates are hooked on to the line and dragged from one
location within the factory to another across a series of rollers.

the original problem was at :https://www.physicsforums.com/showthread.php?t=521477
On there also has an image of what i mean since it won't let me upload it twice.

I have currently calculated:

horrizontal component acting on the crate
the acceleration experienced by the crate
the speed of the crate at the end of a 20m journey
the kinetic energy of the crate at the end of the journey
the duration of the journey

It now wants the Work done on the crate during the journey

If that's any better, Cheers
 
joe465 said:
It now wants the Work done on the crate during the journey
You've calculated it correctly.
 
Thankyou very much for your time and help
 

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