How Is Work Calculated in Elliptical Orbits?

Click For Summary
SUMMARY

Work in elliptical orbits is calculated using the dot product of the force vector and the displacement vector. In this context, centripetal acceleration is defined as velocity squared divided by radius, which, when multiplied by mass, yields the force. The discussion emphasizes that work is only done when there is motion in the same direction as the force, clarifying that parallel forces contribute to acceleration while perpendicular forces do not perform work. Understanding these principles is crucial for accurately analyzing motion in elliptical orbits.

PREREQUISITES
  • Understanding of vector mathematics, specifically dot products
  • Familiarity with centripetal acceleration and its formula
  • Knowledge of gravitational forces and their effects on orbital motion
  • Basic physics concepts related to work and energy
NEXT STEPS
  • Study the principles of orbital mechanics, focusing on elliptical orbits
  • Learn about the mathematical derivation of centripetal acceleration
  • Explore the concept of force components in physics, particularly in circular and elliptical motion
  • Investigate the application of the work-energy theorem in non-uniform motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and orbital dynamics, as well as educators looking to clarify concepts related to work in elliptical orbits.

CaptainADHD
Messages
53
Reaction score
0

Homework Statement



http://img47.imageshack.us/img47/7206/wtffffftv0.th.jpg http://g.imageshack.us/thpix.php

Homework Equations



Work is the dot product of force vector and displacement vector. Centripetal acceleration is velocity squared divided by radius -- multiply by mass to get force.

The Attempt at a Solution



Parallel does no work, perpendicular speeds it up ----->>> which is wrong (failed this question).

I understand that objects in circular orbit have zero acceleration and thus constant speed. But with elliptical orbits, the body is speeding up or slowing down depending on its position relative to the body exerting gravitational force upon it.

What exactly is parallel to the planet itself? I'm having a hard time understanding how to apply force components when I don't know what the angles are.
 
Last edited by a moderator:
Physics news on Phys.org
If I'm following this correctly, it will be the reverse answer of what you gave. Work is done only if there is some motion in the same direction of the force. By parallel, they mean parallel to the movement of the planet, or in the same direction as the V arrow. Perpendicular is perpendicular to the motion, or the force that tries to smash the planet into the sun. It doesn't move that way, so no work by perpendicular, and parallel speeds it up.
 
krausr79 said:
If I'm following this correctly, it will be the reverse answer of what you gave. Work is done only if there is some motion in the same direction of the force. By parallel, they mean parallel to the movement of the planet, or in the same direction as the V arrow. Perpendicular is perpendicular to the motion, or the force that tries to smash the planet into the sun. It doesn't move that way, so no work by perpendicular, and parallel speeds it up.

Thanks
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 19 ·
Replies
19
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
4K
Replies
17
Views
2K
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 12 ·
Replies
12
Views
1K