How Is Work Done by Gravitational Force Calculated in Satellite Orbits?

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The discussion revolves around calculating the work done by gravitational force on a satellite with a mass of 7655 kg in an elliptical orbit, specifically from apogee to perigee and vice versa. The satellite's speeds at these points are 2880 m/s and 8396 m/s, respectively. Participants express confusion about the concept of work and the relevant equations needed for the calculations. One user questions the motivation behind attempting the problem without a foundational understanding. The thread highlights the need for clarity on the work-energy theorem and its application in orbital mechanics.
emmah01
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1. Homework Statement

A 7655 kg satellite has an elliptical orbit. The point on the orbit that is farthest from the Earth is called the apogee and is at the far right side of the drawing. The point on the orbit that is closest to the Earth is called the perigee and is at the far left side of the drawing. Suppose that the speed of the satellite is 2880 m/s at the apogee and 8396 m/s at the perigee. Find the work done by the gravitational force when the satellite moves from a) the apogee to the perigee and b) the perigee to the apogee?

2. Homework Equations

No idea...

The Attempt at a Solution



Honestly I don't even have a clue how to start this...anyone who can help, thank you!

Homework Statement


2. Homework Equations
3. The Attempt at a Solution
 
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What is 'work'? Have you heard of the 'word-energy theorem'?
 
emmah01 said:
Honestly I don't even have a clue how to start this...

That being the case I have to ask, why are you even trying it? If it is part of a class you should have SOME idea how to start it.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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