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How is Zp solved for in this problem? (Answer given)

  1. Feb 10, 2017 #1
    Given:
    Rs = 0.20 Ω
    R'r = 0.17 Ω
    Xs = 0.50 Ω
    X ' r = 0.60 Ω
    Rc = 200 Ω
    Xm = 15 Ω
    Solution:
    at Nr = 1165, slip = (Ns- Nr)/Ns = 0.02916 ~2.92%slip
    at Nr = 1195, slip = (Ns- Nr)/Ns = 0.00416 ~0.42%slip
    Zp = j Xm || ( (R'r / s) + j X'r )
    therefore for i) slip s = 0.02916
    Zp = 5.2787 <26.36' or 4.7295 + 2.344j
    Ztotal = Zs + Zp = ( 0.2 + 0.5j) + (4.7295 + 2.344j) = 5.69<29.98'
    What do the double vertical lines mean in this case, and how is the Zp equation solved? Please show work, thank you. Also how was that equation created? (Trying to study, thanks guys)
     
  2. jcsd
  3. Feb 10, 2017 #2

    berkeman

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    Staff: Mentor

    Welcome to the PF.

    Double vertical or // lines usually means "in parallel with".

    Can you post the circuit, and say how you think the problem was solved? Thanks.
     
  4. Feb 10, 2017 #3

    LvW

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    Adam - do you really expect that somebody can understand how the various symbols are formed into a circuit?
     
  5. Feb 10, 2017 #4

    NascentOxygen

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    Staff: Mentor

    That is not a "less than" sign, it's the angle of the "vector" whose length is 5.2787
    An equivalent way to write a vector is as its x-component and y-component, and in this case it is shown as a complex number, 4.7295 + ##j## 2.344
     
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