How Long Before an Oscillator's Energy Halves?

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Homework Help Overview

The problem involves a mass-spring oscillator with a specified period and a damping factor affecting its amplitude over time. The original poster seeks to determine the time required for the oscillator's energy to halve due to this damping effect.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use logarithmic equations to relate energy decay to time, but expresses uncertainty about the approach. A participant clarifies the interpretation of the variable "t" in the equation as representing cycles rather than seconds.

Discussion Status

The discussion has progressed with clarifications provided regarding the interpretation of the original poster's calculations. The original poster indicates a willingness to reattempt the problem after receiving feedback.

Contextual Notes

There is an emphasis on understanding the relationship between cycles of oscillation and time, as well as the impact of damping on energy reduction. The original poster's initial calculation was based on an incorrect interpretation of the variables involved.

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Homework Statement



A mass M is suspended from a spring and oscillates with a period of .940s. Each complete oscillation results in an amplitude reduction of a factor of .96 due to a small velocity dependent of frictional effect. Calculate the time it takes for the total energy of the oscillator to decrease to .50 of its initial value.

Homework Equations



unsure... A=Ao*factor^N

The Attempt at a Solution



I am unsure how to approach this. I did

log .50 = t log(.96)^2
t= log(.50)/log(.96)^2
t=8.48 s

but that was incorrect. Can someone please tell me what I am doing wrong?
 
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In you equation

log .50 = t log(.96)^2,

"t" isn't the time in seconds, it's the number of cycles of oscillation when the energy has decayed to .50 of the original value.

You want to time for 8.48 cycles with a period of 0.940 sec/cycle.
 
Oh, I see now. I think I can handle the equation from here. Well, I'm going to attempt the problem again to make sure :smile:
 
Yes, I got it correct, thank you AlephZero!
 

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