How Long Does an Electron Stay in the Hydrogen 2p State?

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SUMMARY

The discussion focuses on the lifetime of an electron in the 2p state of hydrogen before transitioning to the 1s state. The formula provided, W = (4*α*ω³)/(3*c²)*|r12|², defines the transition rate, where α is the fine structure constant, ω is the energy difference, and c is the speed of light. The lifetime of the electron is determined as τ = 1/W. Clarification is sought regarding the calculation of |r12|², specifically whether it should be computed as a combined expectation value or separately for each Cartesian coordinate.

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  • Understanding of quantum mechanics principles, specifically electron states in hydrogen.
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thesage
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The problem statement
An electron going from 2p to 1s state in hydrogen sits up at the 2p for a while then jumps down.
with the given eqn
[itex]W=\frac {4*\alpha*\omega^3}{3*c^2}*\mid r12\mid^2[/itex]
[itex]\mid r12\mid^2=\mid<1\mid x\mid2>\mid^2+\mid<1\mid y\mid2>\mid^2+\mid<1\mid z\mid2>\mid^2[/itex]

alpha is fine structure cons, omega is the energy diff and c is speed of light

I'd imagine the life time is 1/W as the rate is per second.

The attempt at a solution
The question is okay except for the [itex]\mid r12\mid^2[/itex] part. Is the [itex]\mid r12\mid^2 part the expectation value of r or do i need to do the x,y,z separatly. The statement, in the question, of what [itex]\mid r12\mid^2 is confuses me.[/itex][/itex]
 
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You have to do it separately, the expectation value is the matrix element of an operator between the same states, here you have two different states.
 

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