How Long Does It Take a Feather to Fall 1.4 Meters on the Moon?

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SUMMARY

A feather dropped from a height of 1.40 meters on the Moon, where the acceleration due to gravity is 1.67 m/s², takes 1.29 seconds to reach the surface. The correct equation to determine the time of fall is derived from the formula d = vi + 1/2 * at², where initial velocity (vi) is zero. The user initially attempted to use vf = vi + at but did not arrive at the correct solution. After recalculating with the appropriate formula, the user confirmed the correct time of fall.

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A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s2 Determine the time for the feather to fall to the surface of the moon.

So, I wrote my given:
d=1.4 m
a= 1.67 m/s2
both initial and final velocity= 0

I know I am looking for time, but I have no idea what equation to use. I tried:
vf= vi+at , but I didn't get the right answer. The answer should be 1.29 s.
Any help would be much appreciated, please and thank you!:)
 
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Well what equation involves d,a,t and u (initial velocity)?
 
This does: d=vi+1/2*at2
but I didn't get the right answer with that either, I got .75:(
 
I got the right answer now.:)
 

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