How Long Does It Take for a Bullet to Stop in Wood?

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SUMMARY

The discussion centers on calculating the time it takes for a .22 rifle bullet, traveling at 350 m/s, to stop after penetrating 0.130 m into a block of soft wood. The bullet has a mass of 1.80 g, and a constant retarding force is assumed. To find the stopping time, one must first determine the required acceleration using kinematic equations, specifically x(t) = x0 + v0*t + (1/2)*a*t^2, and then apply Newton's second law to calculate the force exerted by the wood on the bullet.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of Newton's laws of motion
  • Basic principles of force and acceleration
  • Ability to perform unit conversions (grams to kilograms)
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  • Calculate the acceleration required to stop the bullet using kinematic equations
  • Determine the force exerted by the wood on the bullet using Newton's second law
  • Explore the concept of constant retarding force in motion
  • Review examples of projectile motion and impact forces
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Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators looking for practical examples of force and motion calculations.

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momentum question...REALLY NEED HELP!

Homework Statement


A .22 rifle bullet, traveling at 350 m/s, strikes a block of soft wood, which it penetrates to a depth of 0.130m . The block of wood is clamped in place and doesn't move. The mass of the bullet is 1.80g. Assume a constant retarding force.

??-How much time is required for the bullet to stop? (in seconds)

??-What force, in Newtons, does the wood exert on the bullet?


Homework Equations





The Attempt at a Solution


well honestly, i have no idea where to begin... can some one please help me

 
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Kinematics, think x(t)=x0+v0*t+(1/2)*a*t^2. What acceleration is required to stop the bullet? Once you have a, what force is needed to stop the bullet? Now think of Newton's third law.
 

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