How Long Does It Take for a Dropped Packet to Hit the Ground?

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SUMMARY

The discussion focuses on calculating the time it takes for a packet dropped from a helicopter, ascending at 8 m/s from a height of 122.8 m, to reach the ground. The relevant equations include vf = vi + gt, S = vit + 1/2gt², and 2aS = vf² - vi². The initial velocity (vi) of the packet is 8 m/s upwards, and the gravitational acceleration (g) is -9.81 m/s². The solution requires determining which equation best fits the scenario to solve for time (t).

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Homework Statement



A Helicopter is vertically moving upward with speed of 8m/s.At a height of 122.8m from ground,a packet is fallen from the Heli window.How much time would the packet take for hitting to ground?

Homework Equations



vf=vi+gt.
S=vit+1/2gt^2
2aS=vf^2-vi^2

The Attempt at a Solution

 
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You have the initial speed of the packet, also the distance from the ground, and you are required to find t,
Which of the three equations you going to use?
a.) vf=vi+gt.
b.) S=vit+1/2gt^2
c.) 2aS=vf^2-vi^2
 
shehri said:

Homework Statement



A Helicopter is vertically moving upward with speed of 8m/s.At a height of 122.8m from ground,a packet is fallen from the Heli window.How much time would the packet take for hitting to ground?

Homework Equations



vf=vi+gt.
S=vit+1/2gt^2
2aS=vf^2-vi^2

The Attempt at a Solution


Well... what have you tried? Show your work please.
 

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