How Long Does It Take for a Patrol Car to Catch a Speeder?

  • Thread starter Thread starter kinematics23
  • Start date Start date
  • Tags Tags
    Acceleration
Click For Summary
SUMMARY

The problem involves a speeder traveling at 109 km/h and a patrol car that accelerates from rest at 8 km/h/s until it reaches a maximum speed of 141 km/h. To determine how long it takes for the patrol car to catch the speeder, the solution requires splitting the problem into two parts: first calculating the time taken for the patrol car to reach its top speed and the distance covered during this acceleration, and then determining the time taken to catch the speeder at constant speed. The initial attempt yielded an incorrect time of 27.3 seconds, indicating a need for a more structured approach to the calculations.

PREREQUISITES
  • Understanding of kinematic equations, specifically Δx = v₀t + 1/2at²
  • Knowledge of constant acceleration and maximum speed concepts
  • Ability to solve equations involving two moving objects
  • Familiarity with unit conversions, particularly between km/h and m/s
NEXT STEPS
  • Calculate the time taken for the patrol car to reach its maximum speed of 141 km/h from rest.
  • Determine the distance traveled by both the speeder and the patrol car during the acceleration phase.
  • Analyze the relative speeds after the patrol car reaches maximum speed to find the catch-up time.
  • Review kinematic equations for two objects in motion to ensure accurate application.
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and motion problems, as well as educators looking for examples of real-world applications of these concepts.

kinematics23
Messages
1
Reaction score
0

Homework Statement


A speeder traveling at a constant speed of
109 km/h races past a billboard. A patrol car
pursues from rest with constant acceleration
of (8 km/h)/s until it reaches its maximum
speed of 141 km/h, which it maintains until it
catches up with the speeder.
How long does it take the patrol car to
catch the speeder if it starts moving just as
the speeder passes? Answer in units of s.

How far does each car travel? Answer in units
of km.


Homework Equations


Δx = volt + 1/2at^2
Δx = 1/2(vo + v)t

The Attempt at a Solution


This is an online assignment I am doing. I tried substituting values for the equations with the given info and tried to make it so the speeder equation and the car equation is the same so I can solve for the time and i got 27.3 but it came out wrong when I entered the question online. Since I cannot get the first part I can't get the second part either.
 
Physics news on Phys.org
You need to split this into two parts. You need to find the time taken for the police car to accelerate to top speed and the distance the policeman and the criminal travel in that time, and then you need to find out how long it takes to catch him at the constant speed and add the two times together.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
1K
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
4
Views
9K
Replies
1
Views
2K
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K