How long does it take for the sun to produce 10,000 KWh on a 31,700 m² surface?

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Homework Help Overview

The discussion revolves around calculating the time it takes for the sun to provide 10,000 KWh of energy on a surface area of 31,700 m², utilizing concepts from thermodynamics and radiative energy transfer.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between energy, power, and time, referencing the Stefan-Boltzmann law and its application to the problem. Questions arise about how to determine total power radiated and the relevance of integration in the context of constant power.

Discussion Status

The discussion is active, with participants providing insights into the relationship between power and energy. Some guidance has been offered regarding the use of the Stefan-Boltzmann law and the implications of constant power in the calculations.

Contextual Notes

Participants are navigating the application of physical laws and equations, with some uncertainty about the integration process and the assumptions underlying the problem setup.

Dassinia
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Hello

Homework Statement


How much time does it take to the sun to furnish an energy of 10 000 KWh on a surface of 31 700 m².


Homework Equations


Stefan-Boltzmann law ?
the power radiated from a black body = σ*T4



The Attempt at a Solution


I don't know how I can find the time, I don't know any equation that depend on t to find it, if someone can explain me, that would be great !
Thank you !
 
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Hmm, so you don't know where time comes in? You know the total energy that must be provided. You also know the power. What is the relationship between energy and power? This will answer your question...
 
Hello,
Pavg=E/τ ?
 
Yes, generally power = energy/time (power is the RATE at which energy is produced or expended). So, given that information, how would you solve for time?

Also, you are missing one other thing: the Stefan-Boltzmann law give you the power radiated PER unit area from a blackbody emitter. So how would you determine the total power radiated in this situation?
 
t=E/(σ*T4*31700) ?
Thanks
 
Or I have to use
P=dE/dt
P*dt=dE
∫Pdt=E
∫(σ*T4*31700)dt=E ?
But integrating from what to what ?
 
Dassinia said:
t=E/(σ*T4*31700) ?

Thanks

Yes.

Dassinia said:
Or I have to use
P=dE/dt
P*dt=dE
∫Pdt=E
∫(σ*T4*31700)dt=E ?
But integrating from what to what ?

No, you don't have to integrate, because the power is constant with time, so your equation becomes P = dE/dt = ΔE/Δt, and all you have to to is solve for Δt, as you did above.
 
Ah OK ,
Thank you cepheid !
 

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