How long does it take the giraffe to weigh 85 kg?

  • Thread starter Thread starter Paulo2014
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Homework Help Overview

The problem involves determining the time it takes for a giraffe to reach a weight of 85 kg, based on a quadratic equation that models its weight over the first two years of life. The equation provided is W=(t^2)/4-t+68, where W is the weight in kilograms and t is the time in months since birth.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss rearranging the quadratic equation to solve for t, with some expressing confusion about handling the fractional term. There are suggestions to eliminate fractions and to set the equation equal to zero for solving. Various methods for solving the quadratic equation are explored, including factoring and completing the square.

Discussion Status

The discussion is active, with participants providing guidance on manipulating the equation and exploring different solving techniques. There is recognition of the need to set the equation to zero before solving, and some participants express uncertainty about their approaches. Multiple interpretations of solving the equation are being explored without a clear consensus on the preferred method.

Contextual Notes

Participants mention the importance of reviewing textbook examples and concepts related to quadratic equations, indicating that some foundational knowledge may be lacking. There is also a note about the extraneous nature of negative solutions in the context of time.

  • #31
HallsofIvy said:
No, that's not what he is talking about.

happyg1, you don't have to set an expression to 0 to solve an equation. Here, of course, you could subtract 340 from both sides to get x2- 4t- 68= 0 and try to factor. However, I don't think it will be so easy to factor this.

My favored way of solving x2-4t+ 272=340 would be to subtract 272 from both sides: x2- 4t= 68 and then complete the square.

Can you spell out how to go from there? I've only been thought how to solve for zero, if there is a neat way of doing it for any number I'd like to learn it :)

My approach would be (seeing as it is not a complete square):

x2 -4t -68 = 0

x = -(-4) +- sqrt( (-4)2 - 4 * (-68) ) / 2

x ~= ( 4 +- 16.9 ) / 2

x ~= 10.45 & -6.45

Ah wait, you talk about completing the square. Do you mean like this?

x2- 4t = 68

x2- 4t + 4 = 68 + 4

(x-2)2 = 72

x - 2 ~= +-8.5

x ~= 10.5 & -6.5

If so, I must say I prefer the first. catch-all plug and chug algorithms are neat :)

I need to learn latex.

k
 
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  • #32
kenewbie said:
If so, I must say I prefer the first. catch-all plug and chug algorithms are neat :)

I need to learn latex.

k
Of course. No thinking required!
 

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