kenewbie
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HallsofIvy said:No, that's not what he is talking about.
happyg1, you don't have to set an expression to 0 to solve an equation. Here, of course, you could subtract 340 from both sides to get x2- 4t- 68= 0 and try to factor. However, I don't think it will be so easy to factor this.
My favored way of solving x2-4t+ 272=340 would be to subtract 272 from both sides: x2- 4t= 68 and then complete the square.
Can you spell out how to go from there? I've only been thought how to solve for zero, if there is a neat way of doing it for any number I'd like to learn it :)
My approach would be (seeing as it is not a complete square):
x2 -4t -68 = 0
x = -(-4) +- sqrt( (-4)2 - 4 * (-68) ) / 2
x ~= ( 4 +- 16.9 ) / 2
x ~= 10.45 & -6.45
Ah wait, you talk about completing the square. Do you mean like this?
x2- 4t = 68
x2- 4t + 4 = 68 + 4
(x-2)2 = 72
x - 2 ~= +-8.5
x ~= 10.5 & -6.5
If so, I must say I prefer the first. catch-all plug and chug algorithms are neat :)
I need to learn latex.
k