bob4000
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if a car is moving at 14m/s, and the coefficient of friction is 0.8, what is the distance it takes to stop the car after the brakes are applied locking all four wheels?
The discussion focuses on calculating the stopping distance of a car moving at 14 m/s with a coefficient of friction of 0.8. The process involves drawing a free-body diagram (FBD) to identify the forces acting on the car, specifically the weight, friction, and normal force. The equation 4f = ma is used to derive acceleration, followed by the kinematic equation Vf² = Vi² + 2*a*d to solve for the stopping distance (d) with final velocity (Vf) set to 0. A tutorial link is provided for further learning.
PREREQUISITESThis discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding vehicle dynamics and stopping distances.