How Long for Air Pressure to Drop 30% in Space Capsule with a Hole?

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SUMMARY

The discussion focuses on estimating the time required for air pressure in a spherical space capsule with a radius of 10 meters to drop by 30% after being punctured by a micrometeorite creating a 2mm diameter hole. The relevant equations include the flow rate equation Q = v A and the ideal gas law PV = n R T. The volume of the capsule is calculated as 4188.8 m³, and the area of the hole is determined to be 3.14 x 10^-6 m². The solution involves considering the pressure dynamics as air escapes, with a hint suggesting the answer is approximately 26 days.

PREREQUISITES
  • Understanding of fluid dynamics, specifically Fick's Laws of effusion/diffusion
  • Familiarity with the ideal gas law (PV = nRT)
  • Basic knowledge of calculus for taking derivatives
  • Concept of flow rate in physics (Q = vA)
NEXT STEPS
  • Research the application of Fick's Laws of effusion in real-world scenarios
  • Study the ideal gas law and its implications in varying conditions
  • Learn about the dynamics of pressure changes in closed systems
  • Explore numerical methods for solving differential equations related to gas flow
USEFUL FOR

This discussion is beneficial for physics students, aerospace engineers, and anyone interested in the dynamics of gas behavior in confined spaces, particularly in the context of space exploration and capsule design.

Valour549
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Air pressure drop in Space (please help!)

Homework Statement



A space capsule, which may be treated as a sphere of radius 10 m, is hit by a micrometeorite which makes a hole of diameter 2mm in its skin. Estimate how long it will take for the air pressure to drop by 30%. (Answer should be something like 26 days as a hint).

Homework Equations


Q= v A (Q flow rate, v velocity, A area)
PV = n R T or N k T (P pressure, V volume, n is moles, R gas constant, T temperate, N actual no. of molecules, k Boltzmaan's constant)


The Attempt at a Solution



V = 4188.8 m^3 (sphere's volume), A = 3.14 x 10^-6 m^2 (circle's area)

-I think it has something to do with the above equations, though I'm not entirely sure. Perhaps something to do with Fick's Laws of effusion/diffusion too?

-I think the pressure outside the capsule is zero at all times, so we'll just have to care only about the pressure inside due to the air inside the capsule

-From above, P = N/V * k * T, but pressure changes as air molecules escape (so now time is involved in the equation too), and I'm not sure how to deal with that. Furthermore, what do we put for temperate (absolute zero outside and room temp. inside initially, but that would change pretty fast)?
 
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Consider what values of the ideal gas law are constant with respect to time and those that are changing with time. The hint implies a slow leak so therefore the temperature can be considered constant. Once the constants and variables are determined take the time derivative of the ideal gas equation. This is a start to solving the problem.
 

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