How Long for Electric Field to Vanish in a Photoelectron-Irradiated Capacitor?

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Homework Help Overview

The problem involves a charged, isolated parallel plate capacitor with a vacuum gap, where a short pulse of ultraviolet light generates photoelectrons on the negative plate. The task is to derive an expression for the time taken for the electric field between the plates to vanish after the pulse, given specific parameters.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the electric field created by the photoelectrons and its interaction with the existing field between the plates. Questions are raised about the relationship between energy conservation and transit time, as well as the applicability of Lorentz' law in this context.

Discussion Status

There is an ongoing exploration of the concepts involved, with some participants suggesting potential approaches and clarifying the roles of forces acting on the photoelectrons. While there is no explicit consensus, several lines of reasoning are being examined, indicating a productive discussion.

Contextual Notes

Participants express confusion regarding the appropriate equations and concepts to apply, particularly concerning the effects of the photoelectrons and the nature of the electric field in the capacitor setup.

Onias
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Homework Statement


The negative plate of a charged, isolated parallel plate capacitor with a vacuum gap of width d and carrying a surface charge density s is uniformly irradiated with a short pulse of ultraviolet light whose photon energy is just enough to release a photoelectron at the surface with zero kinetic energy. The radiant energy per unit area deposited by the pulse is such that a photoelectron surface charge density of exactly s is generated. Derive an expression for t_van, the time taken following the ultraviolet pulse for the electric field to vanish everywhere between the plates. Evaluate t_van for s=0.1 micro Coulomb per unit area and d=1mm


Homework Equations


None given


The Attempt at a Solution


I'm very confused by the question, I'm really not sure which equations to use. Presumably, the photoelectron would produce an electric field which would interfere with the two plates, but does this mean I use the equations for polarisation? Thanks in advance.
 
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1. What's the electric field set up by the photon-excited electrons in the gap d?
2. Can you think of a relationship between h and the transit time, based on energy conservation?
 
Could you apply Lorentz' law and calculate the time it would take for the charge to reach the positive plate, when the charges would cancel and, thus, the electric field would vanish? Or am I conceptualizing this wrong?
 
I think you are right. Those photoelectrons got free from the metal at the same time, but with zero kinetic energy, so they are together at the negative plate initially. Feeling the electric field of the positive charges on the other plate, they start to move towards the positive plate together, with the same acceleration and velocity. Arriving there, the charges neutralize and the electric field vanishes.
 
I don't believe there are any magnetic effects to be considered here, so the Lorentz law is not relevant. The inductance of the gap has to be very small.

ehild has the right idea.
 
I might have the name wrong. The force on a charged particle:

F = q(E+(vXB))

Obviously the second term is zero. Anyway, thanks for your help, I have enough info to attempt the question at least :)
 

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