How Long to Double Your Money with Compound Interest?

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SUMMARY

The discussion centers on calculating the time required to double an investment of $30,000 at an annual interest rate of 4.3% compounded annually. The relevant formula for compound interest is S(1 + r)^n, where S is the initial amount, r is the interest rate, and n is the number of years. By setting the equation equal to 2S and solving for n, participants derive that the doubling time can be expressed in terms of logarithms. The pattern established in the calculations confirms the exponential growth of the investment over time.

PREREQUISITES
  • Understanding of compound interest formulas
  • Familiarity with logarithmic functions
  • Basic algebra skills for solving equations
  • Knowledge of financial investment concepts
NEXT STEPS
  • Study the derivation of the compound interest formula
  • Learn how to apply logarithms in financial calculations
  • Explore different compounding frequencies and their effects on investment growth
  • Research financial calculators or software for compound interest computations
USEFUL FOR

Individuals interested in personal finance, students studying finance or mathematics, and anyone looking to understand the implications of compound interest on investments.

jahaddow
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A fixed deposit investment attracts interest of 4.3% p.a. compounded annually. How long will $30 000 take to double in value?
 
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jahaddow said:
A fixed deposit investment attracts interest of 4.3% p.a. compounded annually. How long will $30 000 take to double in value?

What have you tried? What are the relevant equations?
 
This is all I know, I don't know what method should be used to find the answer?
 
That's very peculiar! If you aren't taking a course that has discussed "compound interest", why have you been assigned a problem like this? If you are then surely there are formulas for compound interest in your textbook aren't there?

If I remember correctly, after n years, an amount S at r rate of interest (so that 100r% is the annual percentage rate) compounded annually is given by S(1+ r)^n. Set that equal to 2S, cancel the "S"s and solve for n.
 
A powerful strategy is to think about the specific case and try to obtain a general equation.

The first year, you have $30 000

The second year it is compounded by $30 000 x .043 so you have 30 000 + 30 000 x .043
= 30 000 (1.043)

The next year your money increases again by 30 000 (1.043) (.043) for a total of 30 000 (1.043) + 30 000 (1.043) (.043) = 30 000 (1.043) (1.043) = 30 000 (1.043)^2

By now you should have noticed a pattern.
 

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