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A fixed deposit investment attracts interest of 4.3% p.a. compounded annually. How long will $30 000 take to double in value?
The discussion centers on calculating the time required to double an investment of $30,000 at an annual interest rate of 4.3% compounded annually. The relevant formula for compound interest is S(1 + r)^n, where S is the initial amount, r is the interest rate, and n is the number of years. By setting the equation equal to 2S and solving for n, participants derive that the doubling time can be expressed in terms of logarithms. The pattern established in the calculations confirms the exponential growth of the investment over time.
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jahaddow said:A fixed deposit investment attracts interest of 4.3% p.a. compounded annually. How long will $30 000 take to double in value?