How long would it take for a can of beer to fall over due to quantum tunneling?

In summary, the conversation discusses a solution to a physics problem involving particles at h/2 attempting to tip over a bottle. The concept of tunneling is introduced and the solution suggests that the bottle's center may spontaneously jump to a critical point and tip over. The frequency of attempts is mentioned but not fully understood, and there are questions about setting E=0 and the potential and kinetic energy involved.
  • #1
lackrange
20
0
It's on page 4 (this isn't homework, just something I stumbled upon, it's also in Griffith's 8.17):http://www.physics.udel.edu/~msafrono/425/Lecture 18.pdf .
Can someone help me understand this solution? What exactly is happening...are there particles at h/2 that are smashing against the bottle trying to tip it over? What exactly is tunneling? The solution makes it seem as if it is the center of the bottle that might spontaneously jump up to the critical point and then tip over, but then I don't understand what the frequency of attempts is, why the product should necessarily be 1 (is that just an arbitrary estimate we use for how long it will take to fall over?), and more importantly, why we are setting E=0...they set the potential energy to be 0 at the center of the bottle, but what about kinetic energy?
 
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  • #2
Bump. Any ideas at all would be great.
 
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