How long would it take for a can of beer to fall over due to quantum tunneling?

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SUMMARY

The discussion centers on the concept of quantum tunneling as it relates to the tipping of a can of beer. Participants reference Griffith's 8.17 to explore the mechanics of tunneling, questioning the role of particles at h/2 and the frequency of attempts for the can to tip over. The solution suggests that the center of the bottle may spontaneously jump to a critical point, leading to tipping, while also addressing the potential energy set to zero at this point. Key questions include the rationale behind the frequency of attempts and the treatment of kinetic energy in this context.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly quantum tunneling.
  • Familiarity with potential and kinetic energy concepts.
  • Knowledge of Griffith's quantum mechanics textbook, specifically section 8.17.
  • Basic grasp of particle physics and energy states.
NEXT STEPS
  • Study quantum tunneling in detail, focusing on its implications in particle physics.
  • Review Griffith's quantum mechanics textbook, especially sections related to potential energy and tunneling.
  • Explore the concept of energy states and their significance in quantum mechanics.
  • Investigate the mathematical modeling of spontaneous processes in quantum systems.
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Students and enthusiasts of quantum mechanics, physicists exploring particle behavior, and anyone interested in the implications of quantum tunneling in real-world scenarios.

lackrange
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It's on page 4 (this isn't homework, just something I stumbled upon, it's also in Griffith's 8.17):http://www.physics.udel.edu/~msafrono/425/Lecture 18.pdf .
Can someone help me understand this solution? What exactly is happening...are there particles at h/2 that are smashing against the bottle trying to tip it over? What exactly is tunneling? The solution makes it seem as if it is the center of the bottle that might spontaneously jump up to the critical point and then tip over, but then I don't understand what the frequency of attempts is, why the product should necessarily be 1 (is that just an arbitrary estimate we use for how long it will take to fall over?), and more importantly, why we are setting E=0...they set the potential energy to be 0 at the center of the bottle, but what about kinetic energy?
 
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Bump. Any ideas at all would be great.
 

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