How Many Atoms in 2.5 Moles of NH3?

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Discussion Overview

The discussion revolves around calculating the total number of atoms in 2.5 moles of ammonia (NH3). Participants explore different methods for performing the calculation, focusing on the application of Avogadro's constant and the composition of ammonia molecules.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant proposes multiplying the number of atoms in NH3 by Avogadro's constant to find the total number of atoms.
  • Another participant suggests that the calculation should involve multiplying the number of moles by Avogadro's constant and then by the number of atoms in the molecule.
  • A later reply provides a simplified formula for the calculation: Total atoms = (total moles)(number of atoms in formula)(Avogadro's constant).
  • One participant confirms the total number of atoms calculated as 6.02x10^24.
  • Another participant acknowledges an error in a previous post regarding the composition of ammonia, clarifying that one mole of ammonia contains four moles of atoms.

Areas of Agreement / Disagreement

While there is some agreement on the method of calculation, there is also a correction regarding the interpretation of the number of atoms per mole of ammonia, indicating a lack of consensus on that specific point.

Contextual Notes

The discussion includes varying interpretations of the relationship between moles of ammonia and the number of atoms, with some participants correcting earlier statements without resolving the overall calculation method.

Who May Find This Useful

This discussion may be useful for students learning about stoichiometry, particularly in the context of calculating the number of atoms in chemical compounds.

kasakato
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Homework Statement


What is the total number of atoms in the molecules?
NH3 - 2.5 mole

Homework Equations


Would you multiply the number of atoms in NH3 by Avogadro constant to find the number of atoms?
(4 atoms)(6.02*10^23)
=answer

Or would you multiply the number of moles by Avogadro constant, and then multiply that by the number of atoms?
(2.5 moles)(6.02*10^23)
=x- number of molecules in 2.5mole of NH3

(x)(4 atoms)
=answer
 
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Almost. Set Up the calculation according to your known units. 1 mole of ammonia is composed of 4 atoms. You have how many moles of given ammonia?

2.5 moles ammonia * (4 moles of atoms per mole of ammonia) * (AvogNumber... I will not finish this, but you should try to finish it.
 
Excellent, thank you.

Just to simplify things, as a skeleton formula, it would look like:

Total atoms = (total moles)(number of atoms in formula)(Avg con)

In the case of the original question:
Total atoms=(2.5)(4)(6.02x10^23)
Total atoms= 6.02x10^24
 
kasakato said:
Total atoms= 6.02x10^24

Correct.
 
Borek said:
Correct.

Thanks. :) I finished off the rest of my questions without a hitch.
 
I made an error in post #2, saying:
1 mole of ammonia is composed of 4 atoms.

One mole of ammonia molecules contains FOUR moles of ATOMS.
 

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