How Many Electrons Transfer in a Capacitor Charging at 460V?

[jacksonpeeble]

Homework Statement

A capacitor has a capacitance of 2.56 10-8 F. In the charging process, electrons are removed from one plate and placed on the other plate. When the potential difference between the plates is 460 V, how many electrons have been transferred?

Homework Equations

q=CV
Number of Electrons=q/e

The Attempt at a Solution

q=2.56*10^-6*460=1.1776*10^-5

What is e? I assume this is a constant, but I don't have my book on me to find what it is exactly.

 

[jacksonpeeble]

Nevermind, e=1.6*10^-19, so the final answer is 7.36*10^13. Sorry for the premature post!