- #1

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How to find number of electronics in capacitor?

as 1 coulomb and 1 Amp has 6.25x10^18

on what they depend?

Is this correct..?

Q=C*V

C=47uF and V=12V

Q=47*10^-6*12=5.64*10^-4 Coulmb?????

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- Thread starter ENE
- Start date

- #1

- 42

- 2

How to find number of electronics in capacitor?

as 1 coulomb and 1 Amp has 6.25x10^18

on what they depend?

Is this correct..?

Q=C*V

C=47uF and V=12V

Q=47*10^-6*12=5.64*10^-4 Coulmb?????

- #2

- #3

- 42

- 2

Thanks.

I don't understand this graph

How the capacitor will charge with series Resistance?

I don't understand this graph

How the capacitor will charge with series Resistance?

- #4

Drakkith

Staff Emeritus

Science Advisor

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- #5

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I got

a. The rate of charging is typically described in terms of a time constant RC.

b. The electrical transient phenomena in capacitors and inductors are exponential processes

voltage across the capacitor

how we get exponential here?

- #6

- 46

- 1

Note: you copied images from two different circuit explanations and that's causing confusion. The "Vb" in the first image is "Vs" in the second image.

- #7

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i have to learn this equation?

- #8

Vanadium 50

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- #9

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in electrical engineering how man equation are there?

- #10

jtbell

Mentor

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voltage across the capacitor

how we get exponential here?

We solve the differential equation for the circuit. See for example

http://web.mit.edu/molly/Public/circuits-b.pdf

and scroll down to page W6-6. This uses Q as the variable, not V, but you can change variables using Q = CV if you prefer.

- #11

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- #12

ProfuselyQuarky

Gold Member

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The voltage on a capacitor is Vc = Q / C.

ENE, that's an awfully basic equation, you needn't worryOh, the horror! The horror!

Yes, you have to learn it.

- #13

- #14

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The static electric field is a conservative field. So the work done on a closed path is zero.

WhyThe sum of the voltage drops∆Vi , across any circuit elements that form a closed circuit is zero.??

Do you understand the relationship between work and potential difference?

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