How many equivalent hydrogens are there in octane?

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SUMMARY

The discussion centers on the number of non-equivalent hydrogens in n-octane, with participants debating whether there are 3 or 4 types. The consensus is that while there are 4 distinct types of hydrogens based on substitution tests, only 3 are relevant for NMR shifts due to the influence of nearest-neighbor groups. The conversation highlights the importance of structural isomers and the resolution limits of NMR spectroscopy in distinguishing between chemical shifts of hydrogens on different carbon atoms. Ultimately, the original assertion from Kaplan regarding the number of non-equivalent hydrogens is deemed incorrect.

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MechRocket
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The answer to my Kaplan test (studying for the DAT, just FYI) says 3, but I think it's 4?

Am I wrong?
 
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To which structural isomer of octane are you referring? And do you mean non-equivalent hydrogens?

Assuming you mean n-octane, I think you are correct in principle that there are 4 kinds .. in other words, if you use the substitution test, you can create 4 distinct molecules by substituting a single H-atom with an F-atom. However, for the purpose of determining NMR shifts in alkanes (which I assume is what you are asking about), I am fairly sure that only the nearest-neighbor groups matter. Assuming that is true, can you now see why n-octane has only 3 non-equivalent types of hydrogens?
 
SpectraCat said:
To which structural isomer of octane are you referring? And do you mean non-equivalent hydrogens?

Assuming you mean n-octane, I think you are correct in principle that there are 4 kinds .. in other words, if you use the substitution test, you can create 4 distinct molecules by substituting a single H-atom with an F-atom. However, for the purpose of determining NMR shifts in alkanes (which I assume is what you are asking about), I am fairly sure that only the nearest-neighbor groups matter. Assuming that is true, can you now see why n-octane has only 3 non-equivalent types of hydrogens?

I'd be inclined to disagree there, even for NMR, though for e.g. distinguishing between 3- and 4-halooctanes there may not be that much of a difference in shift, in principle this still exists.
 
sjb-2812 said:
I'd be inclined to disagree there, even for NMR, though for e.g. distinguishing between 3- and 4-halooctanes there may not be that much of a difference in shift, in principle this still exists.

I agree .. in practice it's all a question of resolution. The fact is the the OP is right, and strictly speaking there are 4 non-equivalent types of hydrogens in n-octane. However I am not sure if there is a strong enough magnet to distinguish the difference in chemical shifts of H-atoms on the 3rd and 4th carbons.

However given the phrasing of your post, I think it's important to point out that we are not talking about halo-octanes at all, but just normal n-octane (at least I think so, the OP has still not confirmed that is the correct structural isomer). So, there is no heteroatom in the molecule we are considering .. the substitution test I mentioned is just a thought-experiment to determine chemical non-equivalence. I do agree that if there were a heteroatom in the molecule, the dependence of the chemical shifts of H-atoms on the distance from the substitution site would be more pronounced.
 
Yes, I was talking about n-octane and yes, I meant non-equiv hydrogens.

Thanks guys, I guess Kaplan is wrong here.
 
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