How many equivalent hydrogens are there in octane?

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The answer to my Kaplan test (studying for the DAT, just FYI) says 3, but I think it's 4?

Am I wrong?
 
on Phys.org
To which structural isomer of octane are you referring? And do you mean non-equivalent hydrogens?

Assuming you mean n-octane, I think you are correct in principle that there are 4 kinds .. in other words, if you use the substitution test, you can create 4 distinct molecules by substituting a single H-atom with an F-atom. However, for the purpose of determining NMR shifts in alkanes (which I assume is what you are asking about), I am fairly sure that only the nearest-neighbor groups matter. Assuming that is true, can you now see why n-octane has only 3 non-equivalent types of hydrogens?
 
SpectraCat said:
To which structural isomer of octane are you referring? And do you mean non-equivalent hydrogens?

Assuming you mean n-octane, I think you are correct in principle that there are 4 kinds .. in other words, if you use the substitution test, you can create 4 distinct molecules by substituting a single H-atom with an F-atom. However, for the purpose of determining NMR shifts in alkanes (which I assume is what you are asking about), I am fairly sure that only the nearest-neighbor groups matter. Assuming that is true, can you now see why n-octane has only 3 non-equivalent types of hydrogens?

I'd be inclined to disagree there, even for NMR, though for e.g. distinguishing between 3- and 4-halooctanes there may not be that much of a difference in shift, in principle this still exists.
 
sjb-2812 said:
I'd be inclined to disagree there, even for NMR, though for e.g. distinguishing between 3- and 4-halooctanes there may not be that much of a difference in shift, in principle this still exists.

I agree .. in practice it's all a question of resolution. The fact is the the OP is right, and strictly speaking there are 4 non-equivalent types of hydrogens in n-octane. However I am not sure if there is a strong enough magnet to distinguish the difference in chemical shifts of H-atoms on the 3rd and 4th carbons.

However given the phrasing of your post, I think it's important to point out that we are not talking about halo-octanes at all, but just normal n-octane (at least I think so, the OP has still not confirmed that is the correct structural isomer). So, there is no heteroatom in the molecule we are considering .. the substitution test I mentioned is just a thought-experiment to determine chemical non-equivalence. I do agree that if there were a heteroatom in the molecule, the dependence of the chemical shifts of H-atoms on the distance from the substitution site would be more pronounced.
 
Yes, I was talking about n-octane and yes, I meant non-equiv hydrogens.

Thanks guys, I guess Kaplan is wrong here.
 

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