How Many Functions Have f(1) = f(2)?

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SUMMARY

The discussion focuses on counting the number of functions from set A = {1, 2, 3} to set B = {1, 2, 3, 4, 5} under the condition that f(1) = f(2). The correct calculation reveals that there are 125 total functions (5 choices for each of the three elements in A). Given that f(1) must equal f(2), the number of valid functions is 25, leading to the conclusion that 1/5 of all possible functions satisfy the condition f(1) = f(2).

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Homework Statement


Let A = {1,2,3} and B = {1,2,3,4,5}
Find the number of functions f: A -> B so that f(1) = f(2)


Homework Equations





The Attempt at a Solution



I'm just reviewing random questions for my final on Tuesday and I came upon this question. Seems to be a counting question, and I'm not that sure how to do this since counting questions are more intuition than method (at least that's what I think). Here's what I got:

So a function sends an element from 1 set to another.

There are 3 possible values for the f function, namely f(1), f(2), and f(3).

There are 75 possibilities (5*5*5). So I guess you have to pick the possible values of f(1), f(2) and f(3). So f(1) has 5 choices, f(2) has 1 choice because it must match what f(1) was mapped to, f(3) can be whatever, so it's 5 again.

5 * 1 * 5 = 25

So there are 25 possible functions.

Is this correct? I always hated counting problems ><
 
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Yes, this is right, except that 5*5*5 = 125, not 75.

This then leads to the intuitive result that 1/5 (25/125) of possible functions have f(1) = f(2).
 

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