1. The problem statement, all variables and given/known data An insulated beaker with neglible mass contains .3kg of water at a temp of 78.6 C. How many kg of ice at -19.6 C must be dropped into the water to make Tf= 22.7C? Specific heat for water= 4190 J/kgK specific heat for ice= 2100 J/kgK heat of fusion for water= 334kJ/kg 2. Relevant equations Q=mc(Tf-Ti) Q=mL 3. The attempt at a solution Q1 = bring ice to 0 C Q=micec(Tf-Ti) Q=mice(2100 J/kgK)(0-19.6) Q= 41160mice Q2 = melt ice (phase change) Q=mL Q=mice(334000 J/kg) Q3= cool down water Q=mwaterc(Tf-Ti) Q=(.3kg)(4190 J/kgK)(22.7 - 78.6) Q=-70266.9 J Q1+Q2+Q3=0 41160mice + 334000mice + (-70266.9)=0 375160mice= 70266.9 mice = .187kg This answer isn't correct. What did I do wrong or what did I miss? I'm thinking maybe I missed another Q but I don't know what it could be.