- #1

MattNguyen

- 6

- 0

## Homework Statement

Initially you have mW = 4.6 kg of water at TW = 74°C in an insulated container. You add ice at TI = -19°C to the container and the mix reaches a final, equilibrium temperature of Tf = 33°C. The specific heats of ice and water are cI = 2.10×103 J/(kg⋅°C) and cW = 4.19×103 J/(kg⋅°C), respectively, and the latent heat of fusion for water is Lf = 3.34×105 J/kg.

Enter an expression for the mass of ice you added, in terms of the defined quantities.

## Homework Equations

Q=mL

Q=mcT

## The Attempt at a Solution

I set this up and then solved for MI: mW(TW-Tf)CW - mI(Tf-TI)CI = (mW + MI)L

The program said that there were additional terms in the numerator and denominator, so I don't know what I'm doing wrong.

*m*I =

( mW ( TW - Tf ) cW - mW Lf )/( Lf + ( Tf - TI ) cI )|