How many layers of atoms were deposited on the pennies during the experiment?

  • Thread starter Thread starter rachelle
  • Start date Start date
  • Tags Tags
    Calculations
Click For Summary
SUMMARY

The forum discussion centers on calculating the number of atomic layers deposited on pennies during a plating experiment. Key data includes an increase in mass of 0.0006 g, a density of 7.65 g/cc, and an atomic mass of 32.8 g/mol for the plating material. The surface area of each penny, calculated as 4π(d/2)², is crucial for determining the total area covered by the plated metal. The discussion emphasizes using Avogadro's number to convert mass to the number of atoms, facilitating the calculation of average layers and thickness of the coating.

PREREQUISITES
  • Understanding of basic chemistry concepts such as atomic mass and Avogadro's number.
  • Familiarity with geometric calculations for circular discs.
  • Knowledge of density and its application in mass-volume relationships.
  • Basic skills in unit conversion, particularly between grams and millimoles.
NEXT STEPS
  • Learn how to calculate the surface area of circular discs using the formula 4π(d/2)².
  • Study the application of Avogadro's number in converting grams to the number of atoms.
  • Explore the concept of atomic radius and its role in determining layer thickness.
  • Investigate the principles of electroplating and its effects on mass and density.
USEFUL FOR

This discussion is beneficial for chemistry students, materials scientists, and hobbyists interested in electroplating techniques and atomic layer deposition calculations.

rachelle
Messages
18
Reaction score
0
i don't know where to post this, but we did a little experiment on pennies, and I'm having trouble with analyzing the calculations...

basically the pennies turned into silver, the other gold.. after we heat it, etc

inc. in mass of the pennies .0006 g
density of the solid added to the coins = 7.65 g/cc
atomic mass of the solid added to the coins = 32.8 g/mol
diameter of ea coin = 2.12 cm
thickness of ea coin = 1.59 mm

assume coins are circular discs & atoms are tiny cubes which stack one on top of ea other. calculate the average number of laters of atoms deposited on your coins. also calculate the thickness of this layer

surface area of ea coin, top+bottom+ side = ? sq cm
millimoles of atoms added to surface of coins = ? mmol
total surface area covered y the plated metal (area covered if one atom thick) = ? sq cm
average layers of atoms added = ?
average thickness of plated metal coating = ?

Any Help/Hints? Much appreciated.. thank you
 
Physics news on Phys.org
if we assume coins to be circular, the surface area of the coin can be calculated with \frac {1} {4}\cdot \pi\cdot d^{2}

If you know what the increase in mass of the coin is, you know how many grams of the atoms of the solution is added to the coin.

you can convert that to amount of atoms with the number of Avogadro and if you know the atom radius of the involved atoms, you can calculate the amount of layers on the coin.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
Replies
11
Views
17K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K