How many limit points can be in a countable subset of \mathbb{R}?

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SUMMARY

The discussion focuses on the properties of limit points within subsets of the real numbers, \(\mathbb{R}\). A subset constructed as \(\{ (-1)^n + \frac{1}{n} : n \in \mathbb{N} \}\) has exactly two limit points. The natural numbers, \(\mathbb{N}\), serve as an infinite subset with no limit points. Additionally, the set \(\{1 - \frac{(-1)^n}{n} : n \in \mathbb{N} \}\) is identified as having countably many limit points, while the rational numbers, \(\mathbb{Q}\), contain uncountably many limit points.

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Unassuming
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Could somebody check this to see if I am right?

a.) Construct a subset of [tex]\mathbb{R}[/tex] with exactly two limit points.

[tex]\{ (-1)^n + \frac{1}{n} : n \in \mathbb{N} \}[/tex]


b.) Find an infinite subset of [tex]\mathbb{R}[/tex] with no limit points.

[tex]\mathbb{N}[/tex]

c.) Construct a countable subset of [tex]\mathbb{R}[/tex] with countably many limit points.

[tex]\{1- \frac{(-1)^n}{n}:n \in \mathbb{N} \}[/tex]

d.) Find a countable subset of [tex]\mathbb{R}[/tex] with uncountably many limit points.

[tex]\mathbb{Q}[/tex]
 
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Right. Right. Right. Right. You are getting good at this. Unless in c) you need countably infinity and not just finite.
 

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