How Many Moles of Gas Are in the Bicycle Tire?

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SUMMARY

The calculation of moles of gas in a bicycle tire involves using the Ideal Gas Law, represented by the equation PV = nRT. In this case, the pressure of 734 torr was converted to 0.966 atm, and the temperature of 25 °C was converted to 298.15 K. Substituting these values into the equation yields a total of 0.207 moles of gas. However, this total includes water vapor, indicating that the actual moles of dry gas are less than 0.207 moles.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Ability to convert pressure units (torr to atm)
  • Knowledge of temperature conversion (Celsius to Kelvin)
  • Familiarity with the concept of partial pressures and water vapor
NEXT STEPS
  • Learn about partial pressures and how to calculate them in gas mixtures
  • Study the effects of humidity on gas calculations
  • Explore the application of the Ideal Gas Law in different scenarios
  • Investigate the significance of the gas constant R in various units
USEFUL FOR

Students in chemistry, particularly those studying gas laws, as well as educators and anyone involved in practical applications of gas calculations in real-world scenarios.

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Homework Statement


The air in a bicycle tire is bubbled through water and collected at 25 ^\circ {\rm C}. If the total volume of gas collected is 5.25 L at a temperature of 25 ^\circ {\rm C} and a pressure of 734 torr, how many moles of gas was in the bicycle tire?


Homework Equations


PV = nRT
n=\frac{PV}{RT}

R = .08206

The Attempt at a Solution



1. Convert 734 torr to atm

734/760 = .966 atm

2. Convert 25 ^\circ {\rm C} to K = 298.15 K

3. Plug those all in:

n=\frac{(.966 atn)(5.25 L)}{(.08206)(298.15 K)}

I got n=.207 moles, but the online assignment says I got it wrong.
 
Physics news on Phys.org
0.207 is a correct number of TOTAL moles. Part of this total is water vapour.
 

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