How many moles of valence electrons are in 1 mole of nitride ions?

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SUMMARY

The discussion centers on the number of moles of valence electrons in 1 mole of nitride ions (N3-). It is established that there are 8 valence electrons associated with 1 mole of nitride ions. However, the existence of nitride ions in aqueous or independent gaseous forms is debated, with some participants asserting that nitride ions are a myth. The conversation highlights the complexity of nitrides, emphasizing their presence in ionic lattices and their classification as polar covalent network compounds rather than purely ionic structures.

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  • Familiarity with nitrogen chemistry and its oxidation states
  • Knowledge of lattice structures in solid-state chemistry
  • Basic principles of electron affinity and formal charge
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Homework Statement


The number of moles of valence electrons in 1 mole nitride ions are?


Homework Equations


Nitride ion- N3-


The Attempt at a Solution


The number of electrons are 8.
Therefore number of moles should also be 8?
 
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Nitride ion : N3-. The one you mentioned is Azide ion : N3-.

The rest is correct.
 
That was my typing mistake!
AGNuke said:
Nitride ion : N3-. The one you mentioned is Azide ion : N3-.

The rest is correct.
 
Quite irrelevant to your homework, but the nitride ion is a complete and utter myth. (In spite of what a lot of textbook writers, who really should know better, have to say).

If you could manage to get a nitrogen atom to accept two extra electrons -- in itself a most unlikely feat -- the extra repulsion of those two negative charges to an incoming negatively charged electron would make it quite impossible for the electron to remain anywhere near that particular atom/ion.
 
JohnRC said:
the nitride ion is a complete and utter myth.

Maybe. But Nitrides "exists" in ionic lattice, explain that. But I support the fact that Nitride ions are not present in aqueous form or "maybe" in independent (gaseous) form, but don't outright its existence altogether. This I know that Nitride forms ionic compounds, not covalent compounds.

Come on, even Carbides, Hydrides are present, so why not Nitride? I am pretty sure hydride suffers more than Nitride, as its ionic radius is equivalent to Bromide(!). I would really like to know what you think. You argument seems... weak. Ion will have high potential energy, worse cases also exist.
 
Last edited:
nitrides and carbides are polar covalent network compounds, not ionic lattices. That is why they are hard and refractory. The best calculation methods available show an average charge of approximately 1 electron (not 3) on nitrogen atoms in any refractory nitride.
With carbides, there are non-refractory carbides, e.g. CaC2, but that is an "acetylide" based (notionally) on C22–, an associate base for acetylene acting as an acid. Metallurgists often, and chemists occasionally like to consider compounds like nitrides in a "formal charge" model, where they assign a formal charge of –3 to the nitrogen atoms in a polar network compound. They similarly tend to regard silica, the standard example of a polar network compound, as formally made up of Si4+ and O2– ions. But it is purely a formal accounting, that has nothing to do with reality.

Consider a calcium nitride lattice with a missing electron, and imagine that the lattice is indeed made up of Ca2+ and N3– ions. Will the missing electron attach itself to a calcium ion (electron affinity 11.9 volt) or a "nitride ion" (electron affinity negative)? Having answered this question, it will become obvious to you why in an imaginary ionic lattice made up of these two ions, nearly all of the valence electrons would migrate from the nitrogen atoms to the calcium atoms, resulting in the polar covalent network solid that we actually observe.
 

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