How many nodal and antinodal lines are there?

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SUMMARY

The discussion centers on calculating the wavelength and the number of nodal and antinodal lines in an interference pattern created by two point sources separated by 3.5 cm. The wavelength was determined to be 2.4 cm using the equation PD = d * sin(theta), where the path difference (PD) for the first order nodal line is 0.5λ. It was concluded that there are up to first order antinodal lines and up to second order nodal lines based on the calculated wavelength.

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Homework Statement


In an interference pattern produced by two point sources separated by 3.5cm and vibrating in phase, the first order nodal line forms an angle of 20 degrees with the perpendicular bisector of the line segment joining the two sources. What is the wavelength? How many nodal and antinodal lines are there?


Homework Equations


PD = m * lambda
PD = d * sin(theta)

The Attempt at a Solution


3.5sin20=0.5lambda
lambda = 2.4cm

I'm not sure how to go about calculating the number of lines. The answer is up to first order antinodal and up to 2nd order nodal.
 
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Ilan said:

Homework Statement


In an interference pattern produced by two point sources separated by 3.5cm and vibrating in phase, the first order nodal line forms an angle of 20 degrees with the perpendicular bisector of the line segment joining the two sources. What is the wavelength? How many nodal and antinodal lines are there?


Homework Equations


PD = m * lambda
PD = d * sin(theta)

The Attempt at a Solution


3.5sin20=0.5lambda
lambda = 2.4cm

I'm not sure how to go about calculating the number of lines. The answer is up to first order antinodal and up to 2nd order nodal.

Nodal lines occur in places where the path difference from the sources is 0.5λ, 1.5λ, 2.5λ, ...

If your wavelength of 2.4cm is correct, that means 1.2cm, 3.6cm, 6.0cm , etc .

How do those differences fit alongside a source separation of 3.5 cm ?

Note: I have not checked, at all, the correctness of your λ = 2.4cm answer
 

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