Thomas Young's Double-Slit Experiment Problems

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SUMMARY

The discussion focuses on calculating the wavelength of light used in Thomas Young's Double-Slit Experiment using three different methods. The provided data includes an angle of 1.12° for the 8th maximum, a distance from the slits to the screen of 302 cm, a distance between the first and fifth minimum of 2.95 cm, and a slit separation of 0.00025 m. The calculations consistently yield a wavelength of 611 nm using the equations Δx = λL/d and sinθ = mλ/d. The user expresses confusion regarding the calculation of xn, the distance from a nodal line to the right bisector, and seeks clarification on the definitions of minimum and maximum regions.

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Homework Statement


Determine the wavelength of light being used to create the interference pattern in 3 different ways from the given data.
-The angle to the 8th maximum is 1.12°
-The distance from the slits to the screen is 302 cm
-The distance from the first minimum to the fifth minimum is 2.95 cm
-The distance between the slits is 0.00025 m

Homework Equations


Δx = λL/d
sinθ= mλ/d
sinθ= (n-1/2)λ/d
xn/L=(n-1/2)λ/d
xn/L=mλ/d

The Attempt at a Solution


You know that 4Δx=2.95 so Δx=0.7375
subbing that in you get 0.7375=3.02λ/0.00025
and λ=611 nm

next sin 1.12=8λ/0.00025
and λ= 611 nm

my problem is with the last one. I have no idea how to find xn (the distance between a point on a nodal line and the right bisector) as it is not a given and we don't have any info about the right bisector. So I don't even know how to begin with this problem.

Also, I also want to double check that minimum=nodal region and maximum=antinodal region. A simple fix if I'm wrong but just wanted to double check.

Thanks in advance!
 
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