How many parsecs is it when the redshift z=1

[nenyan]

How to convert red shift to parsecs? Is there a simple converting equation?

 

[George Jones]

How to convert red shift to parsecs?

This depends on which concept of distance is used. See the first paragraph of the attached file.

s there a simple converting equation?

I wrote up an answer for someone else, who specified z = 0.4. I didn't use dimensionless parameters. See the last two graphs in the attached file.

 

[nenyan]

very useful. thanks

 

[Mordred]

This depends on which concept of distance is used. See the first paragraph of the attached file.



I wrote up an answer for someone else, who specified z = 0.4. I didn't use dimensionless parameters. See the last two graphs in the attached file.

thats one of the better quality articles I've read. Far better than some of my attempts lol. Thank you for showing it.

 

[Mordred]

My signature first link has a handy tool called the lightcone calculator here I set stretch to 2.0 for S_upper. S=1+z. I set a randon value for lower stretch.
then I selected the columns I wanted and decimal places. Clicked linear steps.
here is the result with WMAP
flat geometry parameters.

$${\small\begin{array}{|c|c|c|c|c|c|}\hline R_{0} (Gly) & R_{\infty} (Gly) & S_{eq} & H_{0} & \Omega_\Lambda & \Omega_m\\ \hline 14.4&17.3&3400&67.9&0.693&0.307\\ \hline \end{array}}$$ $${\small\begin{array}{|r|r|r|r|r|r|r|r|r|r|r|r|r|r|r|r|} \hline a=1/S&S&z&T (Gy)&D_{now} (Gly)&D_{then}(Gly) \\ \hline 0.500&2.000&1.000&5.8636&11.046&5.523\\ \hline 1.000&1.000&0.000&13.7872&0.000&0.000\\ \hline 1.668&0.599&-0.401&21.7987&6.249&10.425\\ \hline 2.783&0.359&-0.641&30.4437&10.300&28.660\\ \hline 4.642&0.215&-0.785&39.2497&12.776&59.303\\ \hline 7.743&0.129&-0.871&48.0918&14.267&110.467\\ \hline 12.915&0.077&-0.923&56.9418&15.162&195.824\\ \hline 21.544&0.046&-0.954&65.7934&15.698&338.212\\ \hline 35.938&0.028&-0.972&74.6452&16.020&575.729\\ \hline 59.948&0.017&-0.983&83.4973&16.213&971.932\\ \hline 100.000&0.010&-0.990&92.3494&16.328&1632.838\\ \hline \end{array}}$$

the top row has the result you want you just need to convert to parsecs.