How Many Photons Are Needed to Bridge the Band Gap of Fused Silica Glass?

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Homework Help Overview

The problem involves understanding the concept of multiphoton absorption in the context of fused silica glass, specifically determining how many photons of a given wavelength are needed to bridge the material's band gap of 4 eV. The original poster attempts to calculate the energy of a single photon at 800 nm and compare it to the band gap energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of photon energy and the implications of fractional photons, questioning the validity of the original poster's approach and the interpretation of results.

Discussion Status

There is ongoing exploration of the correct method to determine the minimum number of photons required. Some participants offer clarifications on the energy calculations, while others express confusion about the implications of fractional photon values and seek further guidance.

Contextual Notes

Participants are grappling with the concept of energy quantization and how it relates to the band gap, as well as the limitations of the calculations presented. The discussion reflects a mix of attempts to clarify misunderstandings and explore the underlying physics without reaching a definitive conclusion.

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Homework Statement


Glass is transparent to visibile light under normal conditions; however, at extremely high intensities, glass will absorb most of the light incident upon it. This works through a process known as multiphoton absorption. In this process, several photons are absorbed at the same time. If very intense light whose photons carry 2 eV of energy is shined onto a material with a band gap of 4 eV, that light can be absorbed through two-photon absorption, because two photons have the right amount of energy to bridge the band gap. What is the minimum number of photons of 800 nm light that are needed to equal or exceed the band gap of fused silica glass?


Homework Equations


E = hf
c = Yf ... (I mean the Y here to be delta)


The Attempt at a Solution


The energy of a photon with a wavelength of 800 nm is:
f = c/Y = c/(800E-9) = 3.7375E14 Hz
f = 3.7375E14 Hz

E = hf = h(3.37375E14) = 2.476E-19 Joules
E = 2.476E-19 J

The energy of a 800-nm photon is 2.476E-19 Joules per photon.

... The band gap is 4 eV, which = 6.408E-19 J

So I do the band gap energy divided by the energy of one photon to give me the number of photons, right? ...
(6.408E-19 Joules)/ [2.476E-19 Joules/photon] = 2.588 photons.

But MasteringPhysics says no. Where did I go wrong?
 
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What is 0.588 of a photon?
 
Well, yes, that's a bit crazy. But I didn't know any other way to do it, so I just tried putting in whatever I was getting just to try it. Sometimes, MasteringPhysics gives tips on how to go from our wrong answer to the right one.

So then, my method is wrong. How do I do it?
 
A single photon is the base object with energy hc/\lambda. If 2 photons with this wavelength are not enough to bridge the band gap, what is the minimum number of photons that do?
 
Ohh, I see now. The 2.4831E-19 J is per TWO photons, not per one photon. So then my answer would be 6. Thank you for the extra help!
 
No the band gap is equal to 2.588 times the energy of a single photon. What is the smallest number of photons such that their total energy is equal or greater than the band gap?
 

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