How Many Sig Figs Given Error Range?

  • Thread starter Thread starter Cosmophile
  • Start date Start date
  • Tags Tags
    Error Range
Click For Summary
The discussion revolves around determining the appropriate number of significant figures for a calculation result of 1.3250780 x10^7 kg, given a 2% uncertainty. Participants debate whether to report two or three significant figures, considering the ambiguity of the error estimate and its implications on accuracy. The consensus leans towards three significant figures, as the first digit is a 1, which is significant. However, the question is criticized for its lack of clarity and relevance to practical physics problems. Ultimately, the original poster submitted their assignment with two significant figures, expressing frustration with the course's focus on such ambiguous questions.
Cosmophile
Messages
111
Reaction score
2

Homework Statement


"A calculator displays a result as 1.3250780 x10^7 kg. The estimated uncertainty in the result is +/- 2%. How many digits should be included when the result is written?"

Homework Equations


I'm not sure that there are any relevant equations here, aside from (maybe)

Actual result = Measured result + (Measured result)*(+/- 0.02)

The Attempt at a Solution


1.3250780x10^7 = 13250780

13250780*(0.02) = 265016 (rounding to nearest 1)
13240780 + 265016 =
13515795

Where I have bolded the numbers that do not change when the possible error is added to the measured result. Because I am only sure of these two numbers, does that mean that my number of significant figures should be 2?
 
Physics news on Phys.org
Hi Cosmo,

Cosmophile said:
I'm not sure that there are any relevant equations here
Perhaps not equations, but some rules could be mentioned.

An interesting question. Note that even the 2% is an estimate -- and the question doesn't reveal if that estimate is a rough estimate from say, squinting an eye at the scale from which the thirteen million is read off, or if it's an accurate estimate from calculating the standard deviation of a set of a hundred observations. On top of that, the question can be considered ambiguous: it's not clear if 'the result' can include reporting the error or not.

In the former case the answer is easy: (13.2 +/- 0.3) (13.3 +/- 0.3) kilotonne should both be considered reasonable, so three digits.
In the latter case things become really difficult: the tacit assumption is that the error is plus or minus one half of the last digit (i.e. 13 means between 12.5 and 13.5). Then two digits makes one lose accuracy unnecessarily. However, 13.3 would then mean 'in the range [13.25, 13.35]' and that's way too accurate.

My short reply would be: three digits. Main argument: the first digit of the result is a 1. Can you unravel the logic in that ?
 
  • Like
Likes Cosmophile
The question is certainly (hah) flawed, in my opinion. My physics class is being done entirely online, and it is questions like this which cause me to become irritated with the course. Especially when it is my performance in this class which will go on a transcript, and not my ability to solve more "physical" problems, like those posed in Kleppner & Kolenkow.

Woe is me, /plays world's smallest violin.

I've already submitted the assignment (I went with two significant figures, so whoops!) but I appreciate the write-up! I'll give it a moe diligent read when I'm finished with my other assignments. Thank you!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
4
Views
3K
Replies
9
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 3 ·
Replies
3
Views
22K