How Many Significant Figures for Time and Mass Calculations?

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SUMMARY

The discussion focuses on the application of significant figures in calculations involving time and mass. When dividing a time measurement of 21.76 seconds into increments for a centripetal force experiment, the result should retain four significant figures, reflecting the precision of the original measurement. In contrast, when multiplying a mass of 2567 kg by the acceleration due to gravity (g = 9.81 m/s²), the final answer should be reported with three significant figures due to the precision of g. This highlights the importance of understanding how significant figures affect the accuracy of scientific calculations.

PREREQUISITES
  • Understanding of significant figures in scientific measurements
  • Basic knowledge of centripetal force calculations
  • Familiarity with the concept of precision in measurements
  • Knowledge of the acceleration due to gravity (g = 9.81 m/s²)
NEXT STEPS
  • Research the rules for determining significant figures in various mathematical operations
  • Learn about the impact of measurement uncertainty on scientific calculations
  • Explore the principles of centripetal force and its calculations in physics
  • Study the implications of rounding in scientific reporting
USEFUL FOR

This discussion is beneficial for students in physics, educators teaching scientific measurement principles, and professionals involved in experimental design and data analysis.

helpmedude
Hi just a quick question about sig figs. If one was too divide a time such as 21.76s into increments of twenty to find the period of revolution for a centripetal force experiment would the answer be two or four significant figures? also if I multiply a mass such as 2567kg by acceleration due to gravity should my final answer be two significant figures? I am sure the answer to my second question is yes but the first I am not so sure about.
 
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21.76 is 4 sig figures. If you measured say 20 rotations to get this answer then yes, you know the time of one rotation to 4sig figures.

If you have a mass of 2567kg (again to 4 sig fig) and divide by g=9.81 then you only have 3sig figures in you answer. Or more correctly you have mass of 2567 +- 0.5kg and g=9.81 +- 0.005 so you know g to 1 part in 2000 you would know your answer to 1 part in 2000, ie approx +- 1kg.
If you used g=9.7 then you have only 2sig figures and an error of 1 part in 100.
 

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