How Much Acrylic Acid and Sodium Hydroxide Are Needed for 5M Sodium Acrylate?

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SUMMARY

The discussion centers on calculating the amounts of Acrylic Acid (C3H4O2) and Sodium Hydroxide (NaOH) required to achieve a 5 M concentration of Sodium Acrylate (C3H3NaO2). The balanced chemical equation provided is C3H4O2 (liquid) + NaOH → C3H3NaO2 + H2O. Participants emphasize the importance of using minimal quantities of both reactants while achieving the desired molarity, suggesting the use of milliliters for measurement.

PREREQUISITES
  • Understanding of molarity calculations
  • Familiarity with stoichiometry
  • Basic knowledge of chemical equations
  • Experience with unit conversions (mL to liters)
NEXT STEPS
  • Research molarity calculations for solutions
  • Study stoichiometric coefficients in balanced chemical equations
  • Learn about the properties and uses of Sodium Acrylate
  • Explore methods for minimizing reactant usage in chemical reactions
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Chemistry students, educators, and professionals involved in chemical synthesis or formulation who require precise calculations for reactant quantities in reactions.

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Homework Statement


From the balanced equation:

C3H4O2 (liquid) + NaOH → C3H3NaO2 + H2O

Calculate how much Acrylic Acid and Sodium Hydroxide would be needed to have a 5 M concentration in the monomer C3H3NaO2. Use as little Acrylic Acid and Sodium Hydroxide as possible. (Hint: use mL)[/B]

Homework Equations


The Attempt at a Solution


I used a solver, but I got it incorrect on the assignment
 
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