How much additional ethanol can be stored in a cooled steel tank?

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Homework Help Overview

The problem involves determining the additional volume of ethanol that can be stored in a steel tank after cooling from 33.5 degrees Celsius to 16.5 degrees Celsius. The context is related to gas laws and thermal expansion principles.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of the ideal gas law and question its appropriateness for liquids and solids. There is mention of thermal expansion coefficients and the need to consider both the tank and ethanol's volume changes.

Discussion Status

Some participants express confusion about the correctness of the original calculations and the assumptions made. There is acknowledgment that the ideal gas law may not be suitable for this scenario, and guidance is provided regarding the use of thermal expansion equations.

Contextual Notes

Participants note that the problem may not provide all necessary coefficients for thermal expansion, leading to uncertainty in the calculations. There is also mention of discrepancies in how temperature conversions are handled in different contexts.

TFM
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[SOLVED] Gas Laws Problem

Homework Statement



A steel tank is completely filled with 2.90 metres cubed of ethanol when both the tank and the ethanol are at a temperature of 33.5 degrees Celsius.

When the tank and its contents have cooled to 16.5 degrees Celsius, what additional volume of ethanol can be put into the tank?


Homework Equations



\frac{V_1}{T_1} = \frac{V_2}{T_2}

Thus

\frac{V_1*T_2}{T_1} = V_2

Thus V_1-V_2=\Delta V

The Attempt at a Solution



Converting the Temperatures into Kelvin, I get:

\frac{289.65*2.9}{306.65}

This gives a volume of 2.739, and a change in volume of 0.16, but apparently this is incorrect?

TFM
 
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What's the correct answer meant to be?

I can't see what's wrong with that!
 
I'm using Mastering Physics, so it doesn't tell you what the answer should be!

The volume is given in metres cubed, and wanted in meters cubed, I've converted the temperature in Kelvin, so I can't see why it says the answer us wrong?

TFM
 
Personally I don't see what's wrong with your answer - I'm wondering whether mastering physics has incorrectly worked it out without converting to K or maybe it's taking 0 celsius to be 273 K and not 273.15? I don't really know how mastering physics works..
 
Last edited:
Hi TFM,

The equations you are using describe an ideal gas. I think what you need here is the equations describing thermal expansion (and contraction) of solids and liquids. Each material has an expansion coefficient, so you'll need to track how much the tank shrinks in volume as well as how much the ethanol shrinks in volume.
 
alphysicist said:
Hi TFM,

The equations you are using describe an ideal gas. I think what you need here is the equations describing thermal expansion (and contraction) of solids and liquids. Each material has an expansion coefficient, so you'll need to track how much the tank shrinks in volume as well as how much the ethanol shrinks in volume.

Can't dispute that.. but wouldn't have thought that to be taken into consideration if the coefficient wasn't given.
 
Hi astrorob,

astrorob said:
Can't dispute that.. but wouldn't have thought that to be taken into consideration if the coefficient wasn't given.

I not understanding what you mean. What wouldn't need to be taken into consideration? My point was that it's not correct to use the ideal gas law for the contraction of solid steel and liquid ethanol.
 
Yeah my apologies, I've scanned the question without really reading it..Sorry TFM.
 
Ah, I see - we haven't covered that topic yet, I am getting ahead of myself. :rolleyes:

Thanks,

TFM
 
  • #10
Yeah, yu get the right answer using the Thermal Volume Expansion Equations (The coefficient values are given in the textbook that goes with Mastering Physis - You can get MP without the book, then you do have a problem:rolleyes:)

Thanks,

TFM
 

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