How much base to neutralize acid?

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SUMMARY

The discussion centers on the stoichiometric calculation required to neutralize 100 mg of sulfuric acid (H2SO4) with sodium hydroxide (NaOH). The correct amount of NaOH needed for neutralization is 81.6 mg. The user initially attempted to balance the reaction incorrectly, leading to confusion. The proper balanced reaction for the neutralization is H2SO4 + 2NaOH → Na2SO4 + 2H2O, which indicates that two moles of NaOH are required for each mole of H2SO4.

PREREQUISITES
  • Understanding of acid-base neutralization reactions
  • Basic knowledge of stoichiometry
  • Familiarity with molarity calculations
  • Ability to balance chemical equations
NEXT STEPS
  • Study the principles of acid-base reactions in environmental chemistry
  • Learn how to balance chemical equations accurately
  • Explore stoichiometric calculations involving molarity
  • Investigate the properties and applications of strong bases like NaOH
USEFUL FOR

This discussion is beneficial for environmental engineering students, chemistry students, and anyone interested in understanding acid-base neutralization processes in practical applications.

ride5150
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I have a question in my environmental engineering class that goes like this:

if 100mg H2SO4 is added to 1 Liter of water, how many milligrams of NaOH (strong base) must be added to neutralize the acid?

the answer is 81.6mg, but how do i get to the answer?

i tried writing a reaction of: H2SO4 + NaOH = 2H+ + SO2-4 + Na+ + OH-

then doing: molarity of H2SO4 times Molarity of NaOH = 10-7

but i just can't seem to find how to get the answer.

any help would be greatly appreciated
 
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This is a simple stoichiometry. Start by balancing the reaction equation - so far it even doesn't contain correct products, you just dissociated both substances. Do you know how to read balanced reaction equation?
 

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