I have a question in my environmental engineering class that goes like this:(adsbygoogle = window.adsbygoogle || []).push({});

if 100mg H_{2}SO_{4}is added to 1 Liter of water, how many milligrams of NaOH (strong base) must be added to neutralize the acid?

the answer is 81.6mg, but how do i get to the answer?

i tried writing a reaction of: H_{2}SO_{4}+ NaOH = 2H^{+}+ SO^{2-}_{4}+ Na^{+}+ OH^{-}

then doing: molarity of H_{2}SO_{4}times Molarity of NaOH = 10^{-7}

but i just cant seem to find how to get the answer.

any help would be greatly appreciated

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# How much base to neutralize acid?

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