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if 100mg H

_{2}SO

_{4}is added to 1 Liter of water, how many milligrams of NaOH (strong base) must be added to neutralize the acid?

the answer is 81.6mg, but how do i get to the answer?

i tried writing a reaction of: H

_{2}SO

_{4}+ NaOH = 2H

^{+}+ SO

^{2-}

_{4}+ Na

^{+}+ OH

^{-}

then doing: molarity of H

_{2}SO

_{4}times Molarity of NaOH = 10

^{-7}

but i just cant seem to find how to get the answer.

any help would be greatly appreciated